What is the answer to log_{2}(x-3)+log_{2}(x-9)=4 ?

The answer to log_{2}(x-3)+log_{2}(x-9)=4 is x=11

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log_{2}(x-3)+log_{2}(x-9)=4

lo g_{2} (x - 3) + lo g_{2} (x - 9) = 4

x = 11

Solution steps

lo g_{2} (x - 3) + lo g_{2} (x - 9) = 4

Apply log rules

(x - 3) (x - 9) = 16

Solve

(x - 3) (x - 9) = 16 : x = 11, x = 1

x = 11, x = 1

Verify Solutions:

x = 11

True

, x = 1

False

The solution is

x = 11

2 lo g_{10} (x) = 3 lo g_{5} (4)

30 = 85 - 55 lo g_{10} (t + 2)

lo g_{3} (8 x + 1) - lo g_{3} (x - 1) = 2

5.6 = - lo g_{10} (x)

lo g_{2} (x) + lo g_{6} (x) = 3

What is the answer to log_{2}(x-3)+log_{2}(x-9)=4 ?
The answer to log_{2}(x-3)+log_{2}(x-9)=4 is x=11
Solve for x: log_{2}(x-3)+log_{2}(x-9)=4
The solution is x=11