What is the answer to ln(4x)-4ln(x^3)=ln(7) ?

The answer to ln(4x)-4ln(x^3)=ln(7) is x= 1/(e^{\frac{ln(7)-2ln(2)){11}}}

Solve for x: ln(4x)-4ln(x^3)=ln(7)

The solution is x= 1/(e^{\frac{ln(7)-2ln(2)){11}}}

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ln (4 x) - 4 ln (x^{3}) = ln (7)

x = \frac{1}{e ^{\frac{l n ( 7 ) - 2 l n ( 2 )}{11}}}

Decimal Notation

x = 0.95039 \dots

Solution steps

ln (4 x) - 4 ln (x^{3}) = ln (7)

Apply log rules

x = \frac{1}{e ^{\frac{l n ( 7 ) - 2 l n ( 2 )}{11}}}

Verify Solutions:

x = \frac{1}{e ^{\frac{l n ( 7 ) - 2 l n ( 2 )}{11}}}

True

The solution is

x = \frac{1}{e ^{\frac{l n ( 7 ) - 2 l n ( 2 )}{11}}}

lo g_{10} (x) - lo g_{10} (2) = 2

x, y^{2} = ln (x + y)

y, ln (y) = x - 2

lo g_{3} (2 x + 1) = 4

lo g_{10} (- m + 2) = 4

What is the answer to ln(4x)-4ln(x^3)=ln(7) ?
The answer to ln(4x)-4ln(x^3)=ln(7) is x= 1/(e^{\frac{ln(7)-2ln(2)){11}}}
Solve for x: ln(4x)-4ln(x^3)=ln(7)
The solution is x= 1/(e^{\frac{ln(7)-2ln(2)){11}}}