What is the answer to ln(x)+ln(x-4)=5 ?

The answer to ln(x)+ln(x-4)=5 is x=(4+sqrt(16+4e^5))/2

Solve for x: ln(x)+ln(x-4)=5

The solution is x=(4+sqrt(16+4e^5))/2

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ln (x) + ln (x - 4) = 5

x = \frac{4 + 16 + 4 e ^{5}}{2}

Decimal Notation

x = 14.34557 \dots

Solution steps

ln (x) + ln (x - 4) = 5

Apply log rules

x (x - 4) = e^{5}

Solve

x (x - 4) = e^{5} : x = \frac{4 + 16 + 4 e ^{5}}{2}, x = \frac{4 - 16 + 4 e ^{5}}{2}

x = \frac{4 + 16 + 4 e ^{5}}{2}, x = \frac{4 - 16 + 4 e ^{5}}{2}

Verify Solutions:

x = \frac{4 + 16 + 4 e ^{5}}{2}

True

, x = \frac{4 - 16 + 4 e ^{5}}{2}

False

The solution is

x = \frac{4 + 16 + 4 e ^{5}}{2}

lo g_{2} (x + 7) = 2

lo g_{3} (x - 2) = 2

2 + lo g_{3} (x) = lo g_{9} (x)

lo g_{10} (x) = 2 - lo g_{10} (5)

ln (ln (x)) = 7

What is the answer to ln(x)+ln(x-4)=5 ?
The answer to ln(x)+ln(x-4)=5 is x=(4+sqrt(16+4e^5))/2
Solve for x: ln(x)+ln(x-4)=5
The solution is x=(4+sqrt(16+4e^5))/2