What is the answer to 2+log_{3}(x)=log_{9}(x) ?

The answer to 2+log_{3}(x)=log_{9}(x) is x= 1/81

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2+log_{3}(x)=log_{9}(x)

2 + lo g_{3} (x) = lo g_{9} (x)

x = \frac{1}{81}

Decimal Notation

x = 0.01234 \dots

Solution steps

2 + lo g_{3} (x) = lo g_{9} (x)

Apply log rules

x = \frac{1}{81}

Verify Solutions:

x = \frac{1}{81}

True

The solution is

x = \frac{1}{81}

lo g_{10} (x) = 2 - lo g_{10} (5)

ln (ln (x)) = 7

x, - ln (x) = ln (y)

x, ln (2 x + 4) = y - 3

ln (x) - ln (x^{3}) = 8

What is the answer to 2+log_{3}(x)=log_{9}(x) ?
The answer to 2+log_{3}(x)=log_{9}(x) is x= 1/81
Solve for x: 2+log_{3}(x)=log_{9}(x)
The solution is x= 1/81