What is the answer to solvefor x,ln(2x+4)=y-3 ?

The answer to solvefor x,ln(2x+4)=y-3 is x=(e^{y-3}-4)/2

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solvefor x,ln(2x+4)=y-3

solve for

x, ln (2 x + 4) = y - 3

x = \frac{e ^{y - 3} - 4}{2}

Solution steps

ln (2 x + 4) = y - 3

Apply log rules

2 x + 4 = e^{y - 3}

Solve

2 x + 4 = e^{y - 3} : x = \frac{e ^{y - 3} - 4}{2}

x = \frac{e ^{y - 3} - 4}{2}

ln (x) - ln (x^{3}) = 8

lo g_{2} (x + 6) + lo g_{2} (x + 3) = 2

0.87 = lo g_{x} (x)

9 lo g_{5} (x) = 25 lo g_{x} (5)

y, ln (y - 2) = x^{2} + 2

What is the answer to solvefor x,ln(2x+4)=y-3 ?
The answer to solvefor x,ln(2x+4)=y-3 is x=(e^{y-3}-4)/2