What is the answer to log_{9}(30x^2)=7 ?

The answer to log_{9}(30x^2)=7 is x=(729sqrt(3))/(sqrt(10)),x=-(729sqrt(3))/(sqrt(10))

Solve for x: log_{9}(30x^2)=7

The solution is x=(729sqrt(3))/(sqrt(10)),x=-(729sqrt(3))/(sqrt(10))

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lo g_{9} (30 x^{2}) = 7

x = \frac{729 3}{10}, x = - \frac{729 3}{10}

Decimal Notation

x = 399.28974 \dots, x = - 399.28974 \dots

Solution steps

lo g_{9} (30 x^{2}) = 7

Apply log rules

30 x^{2} = 4782969

Solve

30 x^{2} = 4782969 : x = \frac{729 3}{10}, x = - \frac{729 3}{10}

x = \frac{729 3}{10}, x = - \frac{729 3}{10}

lo g_{x} (81) = 8

lo g_{10} (6 x) = - ln (5 x)

ln^{2} (x) = ln (x^{2})

x = 3 lo g_{10} (y^{2}), y

x, y = ln (x y)

What is the answer to log_{9}(30x^2)=7 ?
The answer to log_{9}(30x^2)=7 is x=(729sqrt(3))/(sqrt(10)),x=-(729sqrt(3))/(sqrt(10))
Solve for x: log_{9}(30x^2)=7
The solution is x=(729sqrt(3))/(sqrt(10)),x=-(729sqrt(3))/(sqrt(10))