What is the answer to log_{10}(6x)=-ln(5x) ?

The answer to log_{10}(6x)=-ln(5x) is x=10^{(-log_{10}(5)-log_{10}(6)log_{10}(e))/(log_{10)(e)+1}}

Solve for x: log_{10}(6x)=-ln(5x)

The solution is x=10^{(-log_{10}(5)-log_{10}(6)log_{10}(e))/(log_{10)(e)+1}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{10} (6 x) = - ln (5 x)

x = 1 0^{\frac{- l o g _{10} ( 5 ) - l o g _{10} ( 6 ) l o g _{10} ( e )}{l o g _{10} ( e ) + 1}}

Decimal

x = 0.18925 \dots

Solution steps

lo g_{10} (6 x) = - ln (5 x)

Apply log rules

x = 1 0^{\frac{- l o g _{10} ( 5 ) - l o g _{10} ( 6 ) l o g _{10} ( e )}{l o g _{10} ( e ) + 1}}

Verify Solutions:

x = 1 0^{\frac{- l o g _{10} ( 5 ) - l o g _{10} ( 6 ) l o g _{10} ( e )}{l o g _{10} ( e ) + 1}}

True

The solution is

x = 1 0^{\frac{- l o g _{10} ( 5 ) - l o g _{10} ( 6 ) l o g _{10} ( e )}{l o g _{10} ( e ) + 1}}

ln^{2} (x) = ln (x^{2})

x = 3 lo g_{10} (y^{2}), y

x, y = ln (x y)

lo g_{4} (x - 6) + lo g_{4} (x - 6) = 1

lo g_{x} (0.125) = - 3

What is the answer to log_{10}(6x)=-ln(5x) ?
The answer to log_{10}(6x)=-ln(5x) is x=10^{(-log_{10}(5)-log_{10}(6)log_{10}(e))/(log_{10)(e)+1}}
Solve for x: log_{10}(6x)=-ln(5x)
The solution is x=10^{(-log_{10}(5)-log_{10}(6)log_{10}(e))/(log_{10)(e)+1}}