What is the answer to log_{4}(x-6)+log_{4}(x-6)=1 ?

The answer to log_{4}(x-6)+log_{4}(x-6)=1 is x=8

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log_{4}(x-6)+log_{4}(x-6)=1

lo g_{4} (x - 6) + lo g_{4} (x - 6) = 1

x = 8

Solution steps

lo g_{4} (x - 6) + lo g_{4} (x - 6) = 1

Add similar elements:

lo g_{4} (x - 6) + lo g_{4} (x - 6) = 2 lo g_{4} (x - 6)

2 lo g_{4} (x - 6) = 1

Divide both sides by

2

lo g_{4} (x - 6) = \frac{1}{2}

Apply log rules

x - 6 = 2

Solve

x - 6 = 2 : x = 8

x = 8

Verify Solutions:

x = 8

True

The solution is

x = 8

lo g_{x} (0.125) = - 3

lo g_{10} (5) + lo g_{10} (4 x + 1) = 0

ln (7 x) - 6 ln (x^{2}) = ln (2)

lo g_{x} (3125) = - 5

lo g_{4} (192) - lo g_{4} (3 x) = 2

What is the answer to log_{4}(x-6)+log_{4}(x-6)=1 ?
The answer to log_{4}(x-6)+log_{4}(x-6)=1 is x=8
Solve for x: log_{4}(x-6)+log_{4}(x-6)=1
The solution is x=8