What is the answer to ln(7x)-6ln(x^2)=ln(2) ?

The answer to ln(7x)-6ln(x^2)=ln(2) is x= 1/(e^{\frac{ln(2)-ln(7)){11}}}

Solve for x: ln(7x)-6ln(x^2)=ln(2)

The solution is x= 1/(e^{\frac{ln(2)-ln(7)){11}}}

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ln (7 x) - 6 ln (x^{2}) = ln (2)

x = \frac{1}{e ^{\frac{l n ( 2 ) - l n ( 7 )}{11}}}

Decimal Notation

x = 1.12062 \dots

Solution steps

ln (7 x) - 6 ln (x^{2}) = ln (2)

Apply log rules

x = \frac{1}{e ^{\frac{l n ( 2 ) - l n ( 7 )}{11}}}

Verify Solutions:

x = \frac{1}{e ^{\frac{l n ( 2 ) - l n ( 7 )}{11}}}

True

The solution is

x = \frac{1}{e ^{\frac{l n ( 2 ) - l n ( 7 )}{11}}}

lo g_{x} (3125) = - 5

lo g_{4} (192) - lo g_{4} (3 x) = 2

- 17500 = - (8.314) (298) ln (x)

2 ln (x) - 1 = 0

\frac{1}{x} = e^{- l n (x)}

What is the answer to ln(7x)-6ln(x^2)=ln(2) ?
The answer to ln(7x)-6ln(x^2)=ln(2) is x= 1/(e^{\frac{ln(2)-ln(7)){11}}}
Solve for x: ln(7x)-6ln(x^2)=ln(2)
The solution is x= 1/(e^{\frac{ln(2)-ln(7)){11}}}