What is the answer to log_{4}(192)-log_{4}(3x)=2 ?

The answer to log_{4}(192)-log_{4}(3x)=2 is x=4

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log_{4}(192)-log_{4}(3x)=2

lo g_{4} (192) - lo g_{4} (3 x) = 2

x = 4

Solution steps

lo g_{4} (192) - lo g_{4} (3 x) = 2

Move

lo g_{4} (192)

to the right side

- lo g_{4} (3 x) = 2 - lo g_{4} (192)

Divide both sides by

- 1

lo g_{4} (3 x) = - 2 + lo g_{4} (192)

Apply log rules

3 x = 12

Solve

3 x = 12 : x = 4

x = 4

Verify Solutions:

x = 4

True

The solution is

x = 4

- 17500 = - (8.314) (298) ln (x)

2 ln (x) - 1 = 0

\frac{1}{x} = e^{- l n (x)}

2 ln (x) = - x + 4

lo g_{m} (81) = 4

What is the answer to log_{4}(192)-log_{4}(3x)=2 ?
The answer to log_{4}(192)-log_{4}(3x)=2 is x=4
Solve for x: log_{4}(192)-log_{4}(3x)=2
The solution is x=4