What are the solutions to the equation 8x^2-2x-18=0 ?

The solutions to the equation 8x^2-2x-18=0 are x=(1+sqrt(145))/8 ,x=(1-sqrt(145))/8

Find the zeros of 8x^2-2x-18=0

The zeros of 8x^2-2x-18=0 are x=(1+sqrt(145))/8 ,x=(1-sqrt(145))/8

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8 x^{2} - 2 x - 18 = 0

x = \frac{1 + 145}{8}, x = \frac{1 - 145}{8}

Decimal Notation

x = 1.63019 \dots, x = - 1.38019 \dots

Solution steps

8 x^{2} - 2 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 8 ( - 18 )}{2 \cdot 8}

(- 2)^{2} - 4 \cdot 8 (- 18) = 2145

x_{1, 2} = \frac{- ( - 2 ) \pm 2 145}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 145}{2 \cdot 8}, x_{2} = \frac{- ( - 2 ) - 2 145}{2 \cdot 8}

x = \frac{- ( - 2 ) + 2 145}{2 \cdot 8} : \frac{1 + 145}{8}

x = \frac{- ( - 2 ) - 2 145}{2 \cdot 8} : \frac{1 - 145}{8}

The solutions to the quadratic equation are:

x = \frac{1 + 145}{8}, x = \frac{1 - 145}{8}

\frac{2}{5} = \frac{4}{5} c

15 k^{3} + 90 k^{2} + 120 k

x^{2} - 5 x + 33 = 7 x - 3

8^{x} = 5^{2 x - 1}

\frac{7 x - 4}{3} - \frac{5 - 8 x}{- 3} \geq \frac{4 x - 7}{3}

What are the solutions to the equation 8x^2-2x-18=0 ?
The solutions to the equation 8x^2-2x-18=0 are x=(1+sqrt(145))/8 ,x=(1-sqrt(145))/8
Find the zeros of 8x^2-2x-18=0
The zeros of 8x^2-2x-18=0 are x=(1+sqrt(145))/8 ,x=(1-sqrt(145))/8