What is the answer to log_{3}(x+4)=4+2log_{3}(x) ?

The answer to log_{3}(x+4)=4+2log_{3}(x) is x=(1+sqrt(1297))/(162)

Solve for x: log_{3}(x+4)=4+2log_{3}(x)

The solution is x=(1+sqrt(1297))/(162)

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lo g_{3} (x + 4) = 4 + 2 lo g_{3} (x)

x = \frac{1 + 1297}{162}

Decimal Notation

x = 0.22848 \dots

Solution steps

lo g_{3} (x + 4) = 4 + 2 lo g_{3} (x)

Apply log rules

x + 4 = 81 x^{2}

Solve

x + 4 = 81 x^{2} : x = \frac{1 + 1297}{162}, x = \frac{1 - 1297}{162}

x = \frac{1 + 1297}{162}, x = \frac{1 - 1297}{162}

Verify Solutions:

x = \frac{1 + 1297}{162}

True

, x = \frac{1 - 1297}{162}

False

The solution is

x = \frac{1 + 1297}{162}

lo g_{2} (x^{2} + 3 x - 6) = 2

- 0.73 = 20 lo g_{10} (\frac{x}{5})

lo g_{3} (x) + lo g_{3} (x - 24) = 4

lo g_{\frac{1}{2}} (4 x - 9) = 4

lo g_{10} (9 x) = 3

What is the answer to log_{3}(x+4)=4+2log_{3}(x) ?
The answer to log_{3}(x+4)=4+2log_{3}(x) is x=(1+sqrt(1297))/(162)
Solve for x: log_{3}(x+4)=4+2log_{3}(x)
The solution is x=(1+sqrt(1297))/(162)