What is the answer to log_{2}((r+17)^2)=6 ?

The answer to log_{2}((r+17)^2)=6 is r=-9,r=-25

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log_{2}((r+17)^2)=6

lo g_{2} ((r + 17)^{2}) = 6

r = - 9, r = - 25

Solution steps

lo g_{2} ((r + 17)^{2}) = 6

Apply log rules

(r + 17)^{2} = 64

Solve

(r + 17)^{2} = 64 : r = - 9, r = - 25

r = - 9, r = - 25

lo g_{2} (x) = 100

4 ln (7 x + 4) + 1 = 13

3 lo g_{10} (2 x + 6) = x + 2

13 = - lo g_{10} (x)

ln (e x^{3}) = 2

What is the answer to log_{2}((r+17)^2)=6 ?
The answer to log_{2}((r+17)^2)=6 is r=-9,r=-25
Solve for r: log_{2}((r+17)^2)=6
The solution is r=-9,r=-25