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Popular >

solvefor y,x=ln(2y+1)

Solution

solve for

y, x = ln (2 y + 1)

Solution

y = \frac{e ^{x} - 1}{2}

Solution steps

x = ln (2 y + 1)

Apply log rules

e^{x} = 2 y + 1

Solve

e^{x} = 2 y + 1 : y = \frac{e ^{x} - 1}{2}

y = \frac{e ^{x} - 1}{2}

Popular Examples

ln(x+9)-ln(x+7)=3

ln (x + 9) - ln (x + 7) = 3

log_{10}(x+1)=log_{10}(x)+1

lo g_{10} (x + 1) = lo g_{10} (x) + 1

log_{3}(1/x)=-2

lo g_{3} (\frac{1}{x}) = - 2

log_{2}(x-2)-7=-log_{2}(x+6)

lo g_{2} (x - 2) - 7 = - lo g_{2} (x + 6)

log_{10}(x-21)=2-log_{10}(x)

lo g_{10} (x - 21) = 2 - lo g_{10} (x)

Frequently Asked Questions (FAQ)

What is the answer to solvefor y,x=ln(2y+1) ?
The answer to solvefor y,x=ln(2y+1) is y=(e^x-1)/2