What is the answer to ln(x+2)+ln(x-2)=1 ?

The answer to ln(x+2)+ln(x-2)=1 is x=sqrt(e+4)

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ln(x+2)+ln(x-2)=1

ln (x + 2) + ln (x - 2) = 1

x = e + 4

Decimal Notation

x = 2.59196 \dots

Solution steps

ln (x + 2) + ln (x - 2) = 1

Apply log rules

(x + 2) (x - 2) = e

Solve

(x + 2) (x - 2) = e : x = e + 4, x = - e + 4

x = e + 4, x = - e + 4

Verify Solutions:

x = e + 4

True

, x = - e + 4

False

The solution is

x = e + 4

ln (x + 2) + ln (x - 2) = 0

lo g_{10} (x) + lo g_{10} (2 x) = 1

lo g_{6} (x^{2} + 19 x + 124) = 3

2 = lo g_{5} (x)

0.6 = ln (x)

What is the answer to ln(x+2)+ln(x-2)=1 ?
The answer to ln(x+2)+ln(x-2)=1 is x=sqrt(e+4)
Solve for x: ln(x+2)+ln(x-2)=1
The solution is x=sqrt(e+4)