What is the answer to log_{6}(x^2+19x+124)=3 ?

The answer to log_{6}(x^2+19x+124)=3 is x=4,x=-23

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log_{6}(x^2+19x+124)=3

lo g_{6} (x^{2} + 19 x + 124) = 3

x = 4, x = - 23

Solution steps

lo g_{6} (x^{2} + 19 x + 124) = 3

Apply log rules

x^{2} + 19 x + 124 = 216

Solve

x^{2} + 19 x + 124 = 216 : x = 4, x = - 23

x = 4, x = - 23

2 = lo g_{5} (x)

0.6 = ln (x)

ln (5 x - 1) = 2

lo g_{7} (9 x + 4) + lo g_{7} (x + 2) = 3

4 ln (8 x - 1) + 4 = - 4

What is the answer to log_{6}(x^2+19x+124)=3 ?
The answer to log_{6}(x^2+19x+124)=3 is x=4,x=-23
Solve for x: log_{6}(x^2+19x+124)=3
The solution is x=4,x=-23