What is the answer to log_{2}(x^2-x-6)=2 ?

The answer to log_{2}(x^2-x-6)=2 is x=(1+sqrt(41))/2 ,x=(1-sqrt(41))/2

Solve for x: log_{2}(x^2-x-6)=2

The solution is x=(1+sqrt(41))/2 ,x=(1-sqrt(41))/2

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lo g_{2} (x^{2} - x - 6) = 2

x = \frac{1 + 41}{2}, x = \frac{1 - 41}{2}

Decimal Notation

x = 3.70156 \dots, x = - 2.70156 \dots

Solution steps

lo g_{2} (x^{2} - x - 6) = 2

Apply log rules

x^{2} - x - 6 = 4

Solve

x^{2} - x - 6 = 4 : x = \frac{1 + 41}{2}, x = \frac{1 - 41}{2}

x = \frac{1 + 41}{2}, x = \frac{1 - 41}{2}

x, ln (x) - ln (x - 2) = 1

lo g_{2} (x + 1) + lo g_{2} (x + 2) = 1

ln (1 - x) + ln (1 + x) = - 2

y, z = ln (y + 2) - ln (y + 1)

5000 lo g_{2} (n) = n

What is the answer to log_{2}(x^2-x-6)=2 ?
The answer to log_{2}(x^2-x-6)=2 is x=(1+sqrt(41))/2 ,x=(1-sqrt(41))/2
Solve for x: log_{2}(x^2-x-6)=2
The solution is x=(1+sqrt(41))/2 ,x=(1-sqrt(41))/2