What is the answer to log_{4}(x+17)+log_{4}(x+5)=3 ?

The answer to log_{4}(x+17)+log_{4}(x+5)=3 is x=-1

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log_{4}(x+17)+log_{4}(x+5)=3

lo g_{4} (x + 17) + lo g_{4} (x + 5) = 3

x = - 1

Solution steps

lo g_{4} (x + 17) + lo g_{4} (x + 5) = 3

Apply log rules

(x + 17) (x + 5) = 64

Solve

(x + 17) (x + 5) = 64 : x = - 1, x = - 21

x = - 1, x = - 21

Verify Solutions:

x = - 1

True

, x = - 21

False

The solution is

x = - 1

ln (x) - 3 ln (x) + 2 = 0

lo g_{3} ((2 x^{2} + 5 x + 4) - 7) = 2

ln (2 x + 4) = ln (x + 3)

lo g_{3} (x + 12) = lo g_{3} (5 x)

lo g_{p} (- 1) = n

What is the answer to log_{4}(x+17)+log_{4}(x+5)=3 ?
The answer to log_{4}(x+17)+log_{4}(x+5)=3 is x=-1
Solve for x: log_{4}(x+17)+log_{4}(x+5)=3
The solution is x=-1