What is the answer to log_{p}(-1)=n ?

The answer to log_{p}(-1)=n is No Solution for p\in\mathbb{R}

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log_{p}(-1)=n

lo g_{p} (- 1) = n

No Solution for p \in R

Solution steps

lo g_{p} (- 1) = n

Apply log rules

\frac{ln ( - 1 )}{ln ( p )} = n

Multiply both sides by

ln (p)

\frac{ln ( - 1 )}{ln ( p )} ln (p) = n ln (p)

Simplify

\frac{ln ( - 1 )}{ln ( p )} ln (p) :

Undefined

Undefined = n ln (p)

Switch sides

n ln (p) = Undefined

Divide both sides by

n

ln (p) = \frac{Undefined}{n}

Apply log rules

p = e^{\frac{Undefined}{n}}

Verify Solutions:

p = e^{\frac{Undefined}{n}}

False

The solution is

No Solution for p \in R

lo g_{5} (x - 3) + lo g_{5} (3 x + 1) = 3

lo g_{2 x} (216) = 3

ln (x + 5) = 5 + ln (x)

lo g_{x} (\frac{1}{81}) = - 2

lo g_{2} (x + 3) + lo g_{2} (x - 1) = 5

What is the answer to log_{p}(-1)=n ?
The answer to log_{p}(-1)=n is No Solution for p\in\mathbb{R}