What is the answer to ln(x+5)=5+ln(x) ?

The answer to ln(x+5)=5+ln(x) is x= 5/(e^5-1)

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ln(x+5)=5+ln(x)

ln (x + 5) = 5 + ln (x)

x = \frac{5}{e ^{5} - 1}

Decimal Notation

x = 0.03391 \dots

Solution steps

ln (x + 5) = 5 + ln (x)

Apply log rules

x + 5 = e^{5} x

Solve

x + 5 = e^{5} x : x = \frac{5}{e ^{5} - 1}

x = \frac{5}{e ^{5} - 1}

Verify Solutions:

x = \frac{5}{e ^{5} - 1}

True

The solution is

x = \frac{5}{e ^{5} - 1}

lo g_{x} (\frac{1}{81}) = - 2

lo g_{2} (x + 3) + lo g_{2} (x - 1) = 5

ln (x) = 7.5

lo g_{10} (x) + lo g_{10} (x + 1) = 5

lo g_{2} (ln (x)) = 1

What is the answer to ln(x+5)=5+ln(x) ?
The answer to ln(x+5)=5+ln(x) is x= 5/(e^5-1)
Solve for x: ln(x+5)=5+ln(x)
The solution is x= 5/(e^5-1)