What is the answer to 2ln(7x+4)-13=-1 ?

The answer to 2ln(7x+4)-13=-1 is x=(e^6-4)/7

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2ln(7x+4)-13=-1

2 ln (7 x + 4) - 13 = - 1

x = \frac{e ^{6} - 4}{7}

Decimal Notation

x = 57.06125 \dots

Solution steps

2 ln (7 x + 4) - 13 = - 1

Move

13

to the right side

2 ln (7 x + 4) = 12

Divide both sides by

2

ln (7 x + 4) = 6

Apply log rules

7 x + 4 = e^{6}

Solve

7 x + 4 = e^{6} : x = \frac{e ^{6} - 4}{7}

x = \frac{e ^{6} - 4}{7}

Verify Solutions:

x = \frac{e ^{6} - 4}{7}

True

The solution is

x = \frac{e ^{6} - 4}{7}

lo g_{2} (x^{3} - 48) = 4

lo g_{x} (x - 1) + lo g_{x} (x - 2) = 2

- 2 lo g_{9} (5) = lo g_{9} (x)

ln (x) + ln (x - 2) = 2

ln (x^{2} + 3) - ln (x^{2}) = 1

What is the answer to 2ln(7x+4)-13=-1 ?
The answer to 2ln(7x+4)-13=-1 is x=(e^6-4)/7
Solve for x: 2ln(7x+4)-13=-1
The solution is x=(e^6-4)/7