What is the answer to log_{2}(x+6)+log_{2}(x)=4 ?

The answer to log_{2}(x+6)+log_{2}(x)=4 is x=2

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log_{2}(x+6)+log_{2}(x)=4

lo g_{2} (x + 6) + lo g_{2} (x) = 4

x = 2

Solution steps

lo g_{2} (x + 6) + lo g_{2} (x) = 4

Apply log rules

(x + 6) x = 16

Solve

(x + 6) x = 16 : x = 2, x = - 8

x = 2, x = - 8

Verify Solutions:

x = 2

True

, x = - 8

False

The solution is

x = 2

lo g_{3} (2 x) = 4

lo g_{3} (2 x - 3) = 4

lo g_{2} (2 x + 6) - lo g_{2} (x) = 3

lo g_{4} (x + 1) = 2 + lo g_{4} (3 x - 2)

lo g_{10} (x + 2) + lo g_{10} (4) = 1

What is the answer to log_{2}(x+6)+log_{2}(x)=4 ?
The answer to log_{2}(x+6)+log_{2}(x)=4 is x=2
Solve for x: log_{2}(x+6)+log_{2}(x)=4
The solution is x=2