What is the answer to log_{3}(n^2-3n+5)=2 ?

The answer to log_{3}(n^2-3n+5)=2 is n=4,n=-1

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log_{3}(n^2-3n+5)=2

lo g_{3} (n^{2} - 3 n + 5) = 2

n = 4, n = - 1

Solution steps

lo g_{3} (n^{2} - 3 n + 5) = 2

Apply log rules

n^{2} - 3 n + 5 = 9

Solve

n^{2} - 3 n + 5 = 9 : n = 4, n = - 1

n = 4, n = - 1

0.38 = ln (x)

lo g_{2} (3 x + 1) = lo g_{2} (2 x)

x, lo g_{2} (x + 3) = 5

lo g_{x} (8) = - 2

lo g_{10} (x) + lo g_{10} (30) = 4

What is the answer to log_{3}(n^2-3n+5)=2 ?
The answer to log_{3}(n^2-3n+5)=2 is n=4,n=-1
Solve for n: log_{3}(n^2-3n+5)=2
The solution is n=4,n=-1