What is the answer to log_{9}(3-x)=log_{3}(x-1) ?

The answer to log_{9}(3-x)=log_{3}(x-1) is x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{9}(3-x)=log_{3}(x-1)

lo g_{9} (3 - x) = lo g_{3} (x - 1)

x = 2

Solution steps

lo g_{9} (3 - x) = lo g_{3} (x - 1)

Apply log rules

3 - x = (x - 1)^{2}

Solve

3 - x = (x - 1)^{2} : x = 2, x = - 1

x = 2, x = - 1

Verify Solutions:

x = 2

True

, x = - 1

False

The solution is

x = 2

lo g_{5} (3) + lo g_{5} (x + 2) = 2

(3 - lo g_{3} (x)) lo g_{3 x} (3) = 1

ln (e^{2 x} + 3) = 2 x + ln (3)

lo g_{3} (2 x + 1) = - 1

lo g_{a} (32) = - \frac{5}{2}

What is the answer to log_{9}(3-x)=log_{3}(x-1) ?
The answer to log_{9}(3-x)=log_{3}(x-1) is x=2
Solve for x: log_{9}(3-x)=log_{3}(x-1)
The solution is x=2