What is the answer to log_{3}(2x+1)=-1 ?

The answer to log_{3}(2x+1)=-1 is x=-1/3

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log_{3}(2x+1)=-1

lo g_{3} (2 x + 1) = - 1

x = - \frac{1}{3}

Solution steps

lo g_{3} (2 x + 1) = - 1

Apply log rules

2 x + 1 = \frac{1}{3}

Solve

2 x + 1 = \frac{1}{3} : x = - \frac{1}{3}

x = - \frac{1}{3}

lo g_{a} (32) = - \frac{5}{2}

3.5 = - lo g_{10} (c)

N, x = lo g_{a} (N)

lo g_{3} (1 + lo g_{3} (2 x - 7)) = 1

ln (x - 8) = 5

What is the answer to log_{3}(2x+1)=-1 ?
The answer to log_{3}(2x+1)=-1 is x=-1/3
Solve for x: log_{3}(2x+1)=-1
The solution is x=-1/3