What is the answer to 2ln(x)=log_{e^3}(216) ?

The answer to 2ln(x)=log_{e^3}(216) is x=e^{(ln(6))/2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2ln(x)=log_{e^3}(216)

2 ln (x) = lo g_{e^{3}} (216)

x = e^{\frac{l n ( 6 )}{2}}

Decimal Notation

x = 2.44948 \dots

Solution steps

2 ln (x) = lo g_{e^{3}} (216)

Divide both sides by

2

ln (x) = \frac{lo g _{e^{3}} ( 216 )}{2}

Apply log rules

x = e^{\frac{l n ( 6 )}{2}}

Verify Solutions:

x = e^{\frac{l n ( 6 )}{2}}

True

The solution is

x = e^{\frac{l n ( 6 )}{2}}

lo g_{3} (x) = lo g_{9} (21)

ln (x + 5) = 1 + ln (x)

3 lo g_{3} (x - 2) = 5

lo g_{x - 1} (4) = 2

23 = 10 lo g_{10} (x)

What is the answer to 2ln(x)=log_{e^3}(216) ?
The answer to 2ln(x)=log_{e^3}(216) is x=e^{(ln(6))/2}