What is the answer to log_{10}(x+3)-2log_{10}(x)=1 ?

The answer to log_{10}(x+3)-2log_{10}(x)=1 is x= 3/5

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log_{10}(x+3)-2log_{10}(x)=1

lo g_{10} (x + 3) - 2 lo g_{10} (x) = 1

x = \frac{3}{5}

Solution steps

lo g_{10} (x + 3) - 2 lo g_{10} (x) = 1

Apply log rules

x + 3 = 10 x^{2}

Solve

x + 3 = 10 x^{2} : x = \frac{3}{5}, x = - \frac{1}{2}

x = \frac{3}{5}, x = - \frac{1}{2}

Verify Solutions:

x = \frac{3}{5}

True

, x = - \frac{1}{2}

False

The solution is

x = \frac{3}{5}

lo g_{3} (7 x + 8) = lo g_{3} (7 x + 2)

ln (2 x + 1) = 2 ln (x) + ln (5)

4 ln (3 x - 4) + 16 = 24

lo g_{3} (x) = 3 - lo g_{3} (x + 6)

1 = ln (y)

What is the answer to log_{10}(x+3)-2log_{10}(x)=1 ?
The answer to log_{10}(x+3)-2log_{10}(x)=1 is x= 3/5
Solve for x: log_{10}(x+3)-2log_{10}(x)=1
The solution is x= 3/5