What is the answer to ln(2x+1)=2ln(x)+ln(5) ?

The answer to ln(2x+1)=2ln(x)+ln(5) is x=(1+sqrt(6))/5

Solve for x: ln(2x+1)=2ln(x)+ln(5)

The solution is x=(1+sqrt(6))/5

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ln (2 x + 1) = 2 ln (x) + ln (5)

x = \frac{1 + 6}{5}

Decimal Notation

x = 0.68989 \dots

Solution steps

ln (2 x + 1) = 2 ln (x) + ln (5)

Apply log rules

2 x + 1 = x^{2} \cdot 5

Solve

2 x + 1 = x^{2} \cdot 5 : x = \frac{1 + 6}{5}, x = \frac{1 - 6}{5}

x = \frac{1 + 6}{5}, x = \frac{1 - 6}{5}

Verify Solutions:

x = \frac{1 + 6}{5}

True

, x = \frac{1 - 6}{5}

False

The solution is

x = \frac{1 + 6}{5}

4 ln (3 x - 4) + 16 = 24

lo g_{3} (x) = 3 - lo g_{3} (x + 6)

1 = ln (y)

2 lo g_{2} (x + 2) - lo g_{2} (x + 1) = 2

lo g_{x} (4) = 4 lo g_{x} (x)

What is the answer to ln(2x+1)=2ln(x)+ln(5) ?
The answer to ln(2x+1)=2ln(x)+ln(5) is x=(1+sqrt(6))/5
Solve for x: ln(2x+1)=2ln(x)+ln(5)
The solution is x=(1+sqrt(6))/5