What is the answer to log_{10}(4x)=(-3)/2 ?

The answer to log_{10}(4x)=(-3)/2 is x= 1/(40sqrt(10))

Solve for x: log_{10}(4x)=(-3)/2

The solution is x= 1/(40sqrt(10))

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lo g_{10} (4 x) = \frac{- 3}{2}

x = \frac{1}{40 10}

Solution steps

lo g_{10} (4 x) = \frac{- 3}{2}

Apply log rules

4 x = \frac{1}{10 10}

Solve

4 x = \frac{1}{10 10} : x = \frac{1}{40 10}

x = \frac{1}{40 10}

lo g_{10} (2 x + 1) = lo g_{10} (5)

lo g_{10} (x^{2} + 15 x) = 2

lo g_{9} (9) = 2 lo g_{9} (x)

lo g_{x} (- x + 90) = 2

lo g_{4} (3 x - 8) = 1

What is the answer to log_{10}(4x)=(-3)/2 ?
The answer to log_{10}(4x)=(-3)/2 is x= 1/(40sqrt(10))
Solve for x: log_{10}(4x)=(-3)/2
The solution is x= 1/(40sqrt(10))