What is the answer to log_{10}(2x+1)=log_{10}(5) ?

The answer to log_{10}(2x+1)=log_{10}(5) is x=2

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log_{10}(2x+1)=log_{10}(5)

lo g_{10} (2 x + 1) = lo g_{10} (5)

x = 2

Solution steps

lo g_{10} (2 x + 1) = lo g_{10} (5)

Apply log rules

2 x + 1 = 5

Solve

2 x + 1 = 5 : x = 2

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

lo g_{10} (x^{2} + 15 x) = 2

lo g_{9} (9) = 2 lo g_{9} (x)

lo g_{x} (- x + 90) = 2

lo g_{4} (3 x - 8) = 1

lo g_{2} (x) + lo g_{2} (4 x) - 6 = 0

What is the answer to log_{10}(2x+1)=log_{10}(5) ?
The answer to log_{10}(2x+1)=log_{10}(5) is x=2
Solve for x: log_{10}(2x+1)=log_{10}(5)
The solution is x=2