What is the answer to log_{2}(x)+log_{2}(4x)-6=0 ?

The answer to log_{2}(x)+log_{2}(4x)-6=0 is x=4

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log_{2}(x)+log_{2}(4x)-6=0

lo g_{2} (x) + lo g_{2} (4 x) - 6 = 0

x = 4

Solution steps

lo g_{2} (x) + lo g_{2} (4 x) - 6 = 0

Apply log rules

x = 4

Verify Solutions:

x = 4

True

The solution is

x = 4

lo g_{x + 3} (3 x^{2} - 2 x + 9) = 2

x, y^{6} = ln (x y)

3 ln (16 x^{2} - 8 y) = 0

lo g_{3} (14 - x) = 2

lo g_{4} (3 + x) = 2 + lo g_{4} (x + 1)

What is the answer to log_{2}(x)+log_{2}(4x)-6=0 ?
The answer to log_{2}(x)+log_{2}(4x)-6=0 is x=4
Solve for x: log_{2}(x)+log_{2}(4x)-6=0
The solution is x=4