What is the answer to log_{x+3}(3x^2-2x+9)=2 ?

The answer to log_{x+3}(3x^2-2x+9)=2 is x=4,x=0

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log_{x+3}(3x^2-2x+9)=2

lo g_{x + 3} (3 x^{2} - 2 x + 9) = 2

x = 4, x = 0

Solution steps

lo g_{x + 3} (3 x^{2} - 2 x + 9) = 2

Apply log rules

\frac{ln ( 3 x ^{2} - 2 x + 9 )}{ln ( x + 3 )} = 2

Multiply both sides by

ln (x + 3)

\frac{ln ( 3 x ^{2} - 2 x + 9 )}{ln ( x + 3 )} ln (x + 3) = 2 ln (x + 3)

Simplify

ln (3 x^{2} - 2 x + 9) = 2 ln (x + 3)

Apply log rules

3 x^{2} - 2 x + 9 = (x + 3)^{2}

Solve

3 x^{2} - 2 x + 9 = (x + 3)^{2} : x = 4, x = 0

x = 4, x = 0

Verify Solutions:

x = 4

True

, x = 0

True

The solutions are

x = 4, x = 0

x, y^{6} = ln (x y)

3 ln (16 x^{2} - 8 y) = 0

lo g_{3} (14 - x) = 2

lo g_{4} (3 + x) = 2 + lo g_{4} (x + 1)

lo g_{2 x - 2} (3 x^{2} - 3 x - 2) = 2

What is the answer to log_{x+3}(3x^2-2x+9)=2 ?
The answer to log_{x+3}(3x^2-2x+9)=2 is x=4,x=0
Solve for x: log_{x+3}(3x^2-2x+9)=2
The solution is x=4,x=0