What is the answer to log_{2}(y)+log_{2}(y+1)=1 ?

The answer to log_{2}(y)+log_{2}(y+1)=1 is y=1

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log_{2}(y)+log_{2}(y+1)=1

lo g_{2} (y) + lo g_{2} (y + 1) = 1

y = 1

Solution steps

lo g_{2} (y) + lo g_{2} (y + 1) = 1

Apply log rules

y (y + 1) = 2

Solve

y (y + 1) = 2 : y = 1, y = - 2

y = 1, y = - 2

Verify Solutions:

y = 1

True

, y = - 2

False

The solution is

y = 1

lo g_{10} (x) = - 4.6

lo g_{10} (x - 2) - lo g_{10} (x) = 0

ln (x^{2} + 12 x) = ln (3 x - 18)

lo g_{3} (lo g_{3} (5 x + 2)) = 1

lo g_{a} (a) = \frac{1}{2}

What is the answer to log_{2}(y)+log_{2}(y+1)=1 ?
The answer to log_{2}(y)+log_{2}(y+1)=1 is y=1
Solve for y: log_{2}(y)+log_{2}(y+1)=1
The solution is y=1