What is the answer to ln(x^2+12x)=ln(3x-18) ?

The answer to ln(x^2+12x)=ln(3x-18) is No Solution for x\in\mathbb{R}

Solve for x: ln(x^2+12x)=ln(3x-18)

The solution is No Solution for x\in\mathbb{R}

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ln (x^{2} + 12 x) = ln (3 x - 18)

No Solution for x \in R

Solution steps

ln (x^{2} + 12 x) = ln (3 x - 18)

Apply log rules

x^{2} + 12 x = 3 x - 18

Solve

x^{2} + 12 x = 3 x - 18 : x = - 3, x = - 6

x = - 3, x = - 6

Verify Solutions:

x = - 3

False

, x = - 6

False

The solution is

No Solution for x \in R

lo g_{3} (lo g_{3} (5 x + 2)) = 1

lo g_{a} (a) = \frac{1}{2}

lo g_{3} (4 x + 4) - lo g_{3} (2 - x) = 1

ln (x + 2) - ln (x - 1) = ln (4)

lo g_{8} (16) + lo g_{8} (y - 2) = 2

What is the answer to ln(x^2+12x)=ln(3x-18) ?
The answer to ln(x^2+12x)=ln(3x-18) is No Solution for x\in\mathbb{R}
Solve for x: ln(x^2+12x)=ln(3x-18)
The solution is No Solution for x\in\mathbb{R}