What is the answer to log_{8}(16)+log_{8}(y-2)=2 ?

The answer to log_{8}(16)+log_{8}(y-2)=2 is y=6

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log_{8}(16)+log_{8}(y-2)=2

lo g_{8} (16) + lo g_{8} (y - 2) = 2

y = 6

Solution steps

lo g_{8} (16) + lo g_{8} (y - 2) = 2

Move

lo g_{8} (16)

to the right side

lo g_{8} (y - 2) = 2 - lo g_{8} (16)

Apply log rules

y - 2 = 8^{2 - \frac{4}{3}}

Solve

y - 2 = 8^{2 - \frac{4}{3}} : y = 6

y = 6

Verify Solutions:

y = 6

True

The solution is

y = 6

lo g_{a} (x) = b

4 lo g_{3} (x) - 11 = 5

0 = ln (c)

lo g_{5} (2 x + 1) - lo g_{5} (x - 2) = 1

lo g_{7} (7 x) + 2 lo g_{7} (6) = 3

What is the answer to log_{8}(16)+log_{8}(y-2)=2 ?
The answer to log_{8}(16)+log_{8}(y-2)=2 is y=6
Solve for y: log_{8}(16)+log_{8}(y-2)=2
The solution is y=6