What is the answer to log_{7}(7x)+2log_{7}(6)=3 ?

The answer to log_{7}(7x)+2log_{7}(6)=3 is x= 49/36

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log_{7}(7x)+2log_{7}(6)=3

lo g_{7} (7 x) + 2 lo g_{7} (6) = 3

x = \frac{49}{36}

Solution steps

lo g_{7} (7 x) + 2 lo g_{7} (6) = 3

Move

2 lo g_{7} (6)

to the right side

lo g_{7} (7 x) = 3 - 2 lo g_{7} (6)

Apply log rules

7 x = \frac{343}{36}

Solve

7 x = \frac{343}{36} : x = \frac{49}{36}

x = \frac{49}{36}

Verify Solutions:

x = \frac{49}{36}

True

The solution is

x = \frac{49}{36}

lo g_{2} (3 x + 5) - lo g_{2} (x - 5) = 3

lo g_{3} (10) - lo g_{3} (- 2 x) = 4

lo g_{3} (8 x - 2) + lo g_{3} (x - 1) = 2

lo g_{5} (X) = - 2

ln (3 x + e) = 3

What is the answer to log_{7}(7x)+2log_{7}(6)=3 ?
The answer to log_{7}(7x)+2log_{7}(6)=3 is x= 49/36
Solve for x: log_{7}(7x)+2log_{7}(6)=3
The solution is x= 49/36