What is the answer to log_{3}(8x-2)+log_{3}(x-1)=2 ?

The answer to log_{3}(8x-2)+log_{3}(x-1)=2 is x= 7/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{3}(8x-2)+log_{3}(x-1)=2

lo g_{3} (8 x - 2) + lo g_{3} (x - 1) = 2

x = \frac{7}{4}

Solution steps

lo g_{3} (8 x - 2) + lo g_{3} (x - 1) = 2

Apply log rules

(8 x - 2) (x - 1) = 9

Solve

(8 x - 2) (x - 1) = 9 : x = \frac{7}{4}, x = - \frac{1}{2}

x = \frac{7}{4}, x = - \frac{1}{2}

Verify Solutions:

x = \frac{7}{4}

True

, x = - \frac{1}{2}

False

The solution is

x = \frac{7}{4}

lo g_{5} (X) = - 2

ln (3 x + e) = 3

ln (x^{7}) - ln (x^{4}) = 3

2 = lo g_{b} (900)

3 + lo g_{10} (1 - 3 x) = 0

What is the answer to log_{3}(8x-2)+log_{3}(x-1)=2 ?
The answer to log_{3}(8x-2)+log_{3}(x-1)=2 is x= 7/4
Solve for x: log_{3}(8x-2)+log_{3}(x-1)=2
The solution is x= 7/4