What is the answer to ln(x+11)+ln(x-4)=2ln(x) ?

The answer to ln(x+11)+ln(x-4)=2ln(x) is x= 44/7

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ln(x+11)+ln(x-4)=2ln(x)

ln (x + 11) + ln (x - 4) = 2 ln (x)

x = \frac{44}{7}

Decimal Notation

x = 6.28571 \dots

Solution steps

ln (x + 11) + ln (x - 4) = 2 ln (x)

Apply log rules

(x + 11) (x - 4) = x^{2}

Solve

(x + 11) (x - 4) = x^{2} : x = \frac{44}{7}

x = \frac{44}{7}

Verify Solutions:

x = \frac{44}{7}

True

The solution is

x = \frac{44}{7}

ln (x^{7}) - ln (x^{3}) = 4

lo g_{10} (6 - 2 x) - lo g_{10} (x) = 2

lo g_{10} (t + 3) + lo g_{10} (t) = 1

lo g_{10} (x) + lo g_{10} (x - 4) = 1

ln (x) = 1 - 3 ln (2)

What is the answer to ln(x+11)+ln(x-4)=2ln(x) ?
The answer to ln(x+11)+ln(x-4)=2ln(x) is x= 44/7
Solve for x: ln(x+11)+ln(x-4)=2ln(x)
The solution is x= 44/7