What is the answer to ln(6)+ln(x^2)=ln(2-x) ?

The answer to ln(6)+ln(x^2)=ln(2-x) is x= 1/2 ,x=-2/3

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ln(6)+ln(x^2)=ln(2-x)

ln (6) + ln (x^{2}) = ln (2 - x)

x = \frac{1}{2}, x = - \frac{2}{3}

Decimal Notation

x = 0.5, x = - 0.66666 \dots

Solution steps

ln (6) + ln (x^{2}) = ln (2 - x)

Apply log rules

6 x^{2} = 2 - x

Solve

6 x^{2} = 2 - x : x = \frac{1}{2}, x = - \frac{2}{3}

x = \frac{1}{2}, x = - \frac{2}{3}

Verify Solutions:

x = \frac{1}{2}

True

, x = - \frac{2}{3}

True

The solutions are

x = \frac{1}{2}, x = - \frac{2}{3}

ln (x + 2) = 7

2 ln (3 x^{2}) - ln (x) = 4

y, \frac{1}{2} ln (y) = x

lo g_{10} (x) = - 1.2

- 5 = lo g_{4} (5 x + 9) - 8

What is the answer to ln(6)+ln(x^2)=ln(2-x) ?
The answer to ln(6)+ln(x^2)=ln(2-x) is x= 1/2 ,x=-2/3
Solve for x: ln(6)+ln(x^2)=ln(2-x)
The solution is x= 1/2 ,x=-2/3