What is the answer to log_{8}(2x^2-8x)=2 ?

The answer to log_{8}(2x^2-8x)=2 is x=8,x=-4

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log_{8}(2x^2-8x)=2

lo g_{8} (2 x^{2} - 8 x) = 2

x = 8, x = - 4

Solution steps

lo g_{8} (2 x^{2} - 8 x) = 2

Apply log rules

2 x^{2} - 8 x = 64

Solve

2 x^{2} - 8 x = 64 : x = 8, x = - 4

x = 8, x = - 4

lo g_{10} (5 x - 1) = lo g_{10} (9 x)

lo g_{10} (x) = \frac{3}{2}

x, ln (y) = n ln (x) + c

0.56 = ln (x)

ln (5 x + 3) = 4

What is the answer to log_{8}(2x^2-8x)=2 ?
The answer to log_{8}(2x^2-8x)=2 is x=8,x=-4
Solve for x: log_{8}(2x^2-8x)=2
The solution is x=8,x=-4