What is the answer to ln((x-1)^2)=8 ?

The answer to ln((x-1)^2)=8 is x=e^4+1,x=-e^4+1

Solve for x: ln((x-1)^2)=8

The solution is x=e^4+1,x=-e^4+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

ln ((x - 1)^{2}) = 8

x = e^{4} + 1, x = - e^{4} + 1

Solution steps

ln ((x - 1)^{2}) = 8

Apply log rules

(x - 1)^{2} = e^{8}

Solve

(x - 1)^{2} = e^{8} : x = e^{4} + 1, x = - e^{4} + 1

x = e^{4} + 1, x = - e^{4} + 1

lo g_{9} (x) = 0.25

lo g_{6} (- x^{2} + 37 x) = 2

0 = lo g_{10} (\frac{x - 2}{x + 4}) + 2

3 lo g_{x} (81) = - 12

lo g_{a} (x + 1) = 1 + lo g_{a} (x)

What is the answer to ln((x-1)^2)=8 ?
The answer to ln((x-1)^2)=8 is x=e^4+1,x=-e^4+1
Solve for x: ln((x-1)^2)=8
The solution is x=e^4+1,x=-e^4+1