What is the answer to log_{2}(x+3)+log_{2}(x-4)=3 ?

The answer to log_{2}(x+3)+log_{2}(x-4)=3 is x=5

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log_{2}(x+3)+log_{2}(x-4)=3

lo g_{2} (x + 3) + lo g_{2} (x - 4) = 3

x = 5

Solution steps

lo g_{2} (x + 3) + lo g_{2} (x - 4) = 3

Apply log rules

(x + 3) (x - 4) = 8

Solve

(x + 3) (x - 4) = 8 : x = 5, x = - 4

x = 5, x = - 4

Verify Solutions:

x = 5

True

, x = - 4

False

The solution is

x = 5

lo g_{3} (x - 1) + lo g_{3} (x + 2) = 1

y, lo g_{b} (y) = x

lo g_{10} (3 a) = 0

ln (x) = - ln (x + 1)

lo g_{2} (5 x + 1) = 4

What is the answer to log_{2}(x+3)+log_{2}(x-4)=3 ?
The answer to log_{2}(x+3)+log_{2}(x-4)=3 is x=5
Solve for x: log_{2}(x+3)+log_{2}(x-4)=3
The solution is x=5