What is the answer to ln(x)=1+ln(x+1) ?

The answer to ln(x)=1+ln(x+1) is No Solution for x\in\mathbb{R}

Solve for x: ln(x)=1+ln(x+1)

The solution is No Solution for x\in\mathbb{R}

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ln (x) = 1 + ln (x + 1)

No Solution for x \in R

Solution steps

ln (x) = 1 + ln (x + 1)

Apply log rules

x = e (x + 1)

Solve

x = e (x + 1) : x = \frac{e}{1 - e}

x = \frac{e}{1 - e}

Verify Solutions:

x = \frac{e}{1 - e}

False

The solution is

No Solution for x \in R

lo g_{6} (9) - lo g_{6} (- x) = 2

ln (x^{2} - 3 x + 3) = 0

6 ln (6 x + 1) + 10 = - 2

lo g_{2} ((x + 5)^{4}) = 4

ln (x - 1) = 5

What is the answer to ln(x)=1+ln(x+1) ?
The answer to ln(x)=1+ln(x+1) is No Solution for x\in\mathbb{R}
Solve for x: ln(x)=1+ln(x+1)
The solution is No Solution for x\in\mathbb{R}