What is the answer to log_{6}(9)-log_{6}(-x)=2 ?

The answer to log_{6}(9)-log_{6}(-x)=2 is x=-1/4

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log_{6}(9)-log_{6}(-x)=2

lo g_{6} (9) - lo g_{6} (- x) = 2

x = - \frac{1}{4}

Solution steps

lo g_{6} (9) - lo g_{6} (- x) = 2

Move

lo g_{6} (9)

to the right side

- lo g_{6} (- x) = 2 - lo g_{6} (9)

Divide both sides by

- 1

lo g_{6} (- x) = - 2 + lo g_{6} (9)

Apply log rules

- x = \frac{1}{4}

Solve

- x = \frac{1}{4} : x = - \frac{1}{4}

x = - \frac{1}{4}

Verify Solutions:

x = - \frac{1}{4}

True

The solution is

x = - \frac{1}{4}

ln (x^{2} - 3 x + 3) = 0

6 ln (6 x + 1) + 10 = - 2

lo g_{2} ((x + 5)^{4}) = 4

ln (x - 1) = 5

lo g_{x + 4} (9 x + 16) = 2

What is the answer to log_{6}(9)-log_{6}(-x)=2 ?
The answer to log_{6}(9)-log_{6}(-x)=2 is x=-1/4
Solve for x: log_{6}(9)-log_{6}(-x)=2
The solution is x=-1/4