What is the answer to log_{x+4}(9x+16)=2 ?

The answer to log_{x+4}(9x+16)=2 is x=1,x=0

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log_{x+4}(9x+16)=2

lo g_{x + 4} (9 x + 16) = 2

x = 1, x = 0

Solution steps

lo g_{x + 4} (9 x + 16) = 2

Apply log rules

\frac{ln ( 9 x + 16 )}{ln ( x + 4 )} = 2

Multiply both sides by

ln (x + 4)

\frac{ln ( 9 x + 16 )}{ln ( x + 4 )} ln (x + 4) = 2 ln (x + 4)

Simplify

ln (9 x + 16) = 2 ln (x + 4)

Apply log rules

9 x + 16 = (x + 4)^{2}

Solve

9 x + 16 = (x + 4)^{2} : x = 1, x = 0

x = 1, x = 0

Verify Solutions:

x = 1

True

, x = 0

True

The solutions are

x = 1, x = 0

ln (6.8 x + 2) - 2 = 8

lo g_{10} (3 x) + lo g_{10} (9) = 0

lo g_{10} (x) - lo g_{10} (3) = 2

ln (x) = 42

ln (x) = 2 x

What is the answer to log_{x+4}(9x+16)=2 ?
The answer to log_{x+4}(9x+16)=2 is x=1,x=0
Solve for x: log_{x+4}(9x+16)=2
The solution is x=1,x=0