What is the answer to log_{10}(x^2-3x-10)=2 ?

The answer to log_{10}(x^2-3x-10)=2 is x=(3+sqrt(449))/2 ,x=(3-sqrt(449))/2

Solve for x: log_{10}(x^2-3x-10)=2

The solution is x=(3+sqrt(449))/2 ,x=(3-sqrt(449))/2

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lo g_{10} (x^{2} - 3 x - 10) = 2

x = \frac{3 + 449}{2}, x = \frac{3 - 449}{2}

Solution steps

lo g_{10} (x^{2} - 3 x - 10) = 2

Apply log rules

x^{2} - 3 x - 10 = 100

Solve

x^{2} - 3 x - 10 = 100 : x = \frac{3 + 449}{2}, x = \frac{3 - 449}{2}

x = \frac{3 + 449}{2}, x = \frac{3 - 449}{2}

- lo g_{10} (x) = 4.5

lo g_{7} (X - 2) + lo g_{7} (X + 2) = 1

lo g_{10} (2 x + 5) = 1

ln (x^{3}) + ln (x) = 5

lo g_{5} (4 t + 7) - lo g_{5} (t) = 2

What is the answer to log_{10}(x^2-3x-10)=2 ?
The answer to log_{10}(x^2-3x-10)=2 is x=(3+sqrt(449))/2 ,x=(3-sqrt(449))/2
Solve for x: log_{10}(x^2-3x-10)=2
The solution is x=(3+sqrt(449))/2 ,x=(3-sqrt(449))/2