What is the answer to 6+log_{10}(x)-log_{2}(x)=0 ?

The answer to 6+log_{10}(x)-log_{2}(x)=0 is x= 1/(10^{(6log_{10)(2))/(log_{10)(2)-1}}}

Solve for x: 6+log_{10}(x)-log_{2}(x)=0

The solution is x= 1/(10^{(6log_{10)(2))/(log_{10)(2)-1}}}

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6 + lo g_{10} (x) - lo g_{2} (x) = 0

x = \frac{1}{1 0 ^{\frac{6 l o g _{10} ( 2 )}{l o g _{10} ( 2 ) - 1}}}

Solution steps

6 + lo g_{10} (x) - lo g_{2} (x) = 0

Apply log rules

x = \frac{1}{1 0 ^{\frac{6 l o g _{10} ( 2 )}{l o g _{10} ( 2 ) - 1}}}

Verify Solutions:

x = \frac{1}{1 0 ^{\frac{6 l o g _{10} ( 2 )}{l o g _{10} ( 2 ) - 1}}}

True

The solution is

x = \frac{1}{1 0 ^{\frac{6 l o g _{10} ( 2 )}{l o g _{10} ( 2 ) - 1}}}

lo g_{10} (\frac{4 - 2 x}{2 x}) = 1

lo g_{2} (3 x + 1) = 5

lo g_{10} (x^{2} - 1) = 0

lo g_{10} (x) = - 12.5

lo g_{3} (3 x - 6) = 2

What is the answer to 6+log_{10}(x)-log_{2}(x)=0 ?
The answer to 6+log_{10}(x)-log_{2}(x)=0 is x= 1/(10^{(6log_{10)(2))/(log_{10)(2)-1}}}
Solve for x: 6+log_{10}(x)-log_{2}(x)=0
The solution is x= 1/(10^{(6log_{10)(2))/(log_{10)(2)-1}}}