What is the answer to ln(x-2)+ln(3)=5 ?

The answer to ln(x-2)+ln(3)=5 is x=(e^5)/3+2

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ln(x-2)+ln(3)=5

ln (x - 2) + ln (3) = 5

x = \frac{e ^{5}}{3} + 2

Solution steps

ln (x - 2) + ln (3) = 5

Move

ln (3)

to the right side

ln (x - 2) = 5 - ln (3)

Apply log rules

x - 2 = \frac{e ^{5}}{3}

Solve

x - 2 = \frac{e ^{5}}{3} : x = \frac{e ^{5}}{3} + 2

x = \frac{e ^{5}}{3} + 2

Verify Solutions:

x = \frac{e ^{5}}{3} + 2

True

The solution is

x = \frac{e ^{5}}{3} + 2

ln (x) + ln (2 x) = - 3

lo g_{3} (p) = 7

lo g_{3} (2 x + 3) = 4 - lo g_{3} (x + 6)

lo g_{3} (2) + lo g_{3} (b + 1) = 1

3^{l o g_{x} (81)} = x

What is the answer to ln(x-2)+ln(3)=5 ?
The answer to ln(x-2)+ln(3)=5 is x=(e^5)/3+2
Solve for x: ln(x-2)+ln(3)=5
The solution is x=(e^5)/3+2