What is the answer to log_{9}(2x)-log_{3}(2)=1 ?

The answer to log_{9}(2x)-log_{3}(2)=1 is x=18

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log_{9}(2x)-log_{3}(2)=1

lo g_{9} (2 x) - lo g_{3} (2) = 1

x = 18

Solution steps

lo g_{9} (2 x) - lo g_{3} (2) = 1

Move

lo g_{3} (2)

to the right side

lo g_{9} (2 x) = 1 + lo g_{3} (2)

Apply log rules

2 x = 36

Solve

2 x = 36 : x = 18

x = 18

Verify Solutions:

x = 18

True

The solution is

x = 18

lo g_{3} (4 x - 2) = 4

lo g_{2} (x) = 10000000

0.83 = ln (y)

lo g_{10} (γ) = 0.16096

- 3 lo g_{10} (- 37 x + 1) + 1 = - 8

What is the answer to log_{9}(2x)-log_{3}(2)=1 ?
The answer to log_{9}(2x)-log_{3}(2)=1 is x=18
Solve for x: log_{9}(2x)-log_{3}(2)=1
The solution is x=18