What is the answer to log_{2}(x+5)+log_{2}(x-1)=4 ?

The answer to log_{2}(x+5)+log_{2}(x-1)=4 is x=3

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log_{2}(x+5)+log_{2}(x-1)=4

lo g_{2} (x + 5) + lo g_{2} (x - 1) = 4

x = 3

Solution steps

lo g_{2} (x + 5) + lo g_{2} (x - 1) = 4

Apply log rules

(x + 5) (x - 1) = 16

Solve

(x + 5) (x - 1) = 16 : x = 3, x = - 7

x = 3, x = - 7

Verify Solutions:

x = 3

True

, x = - 7

False

The solution is

x = 3

lo g_{2 x} (4) = 2

lo g_{8} (N) = \frac{1}{3}

2 lo g_{3} (y - 6) - lo g_{3} (y - 4) = 2

5 ln (8 x - 4) + 5 = 25

lo g_{3} ((x + 3) (x - 5)) = 2

What is the answer to log_{2}(x+5)+log_{2}(x-1)=4 ?
The answer to log_{2}(x+5)+log_{2}(x-1)=4 is x=3
Solve for x: log_{2}(x+5)+log_{2}(x-1)=4
The solution is x=3